Here's a puzzle for anybody that would like to take it up today:
I just heard a jet fly overhead. Curious, I went outside. As we all know, sound travels much, much more slowly than light, so the jet was gone from sight by the time I started searching for it, even though it still sounded like it was overhead.
Now, given the speed of sound, and a jet flying at 500 mph, at what elevation would the jet need to fly in order to create the greatest angle between where the sound from the jet is coming from and where the jet actually is?
If anybody wants to kick it around, I'll warn you up front that there are a couple of tricks to finding the solution.
EDIT: As commenter pointed out, the question is a bit incomplete. I'll change that to mean "at what elevation and distance from the observer would the jet need to fly in order to create the greatest angle between where the sound from the jet is coming from and where the jet actually is?"
Assuming we are on planet earth and standing standing still in a flat desert.
Key assumptions are that there is no wind, the speed of the plane is a constant 500 mph, the speed of sound is constant at 760 mph (actually untrue in real life, see http://www.engineeringtoolbox.com/elevation-speed-sound-air-...), the airplane is maintaining a constant elevation, and the curvature of the Earth is irrelevant.
In that situation the actual elevation of the plane doesn't matter. Look at the triangle formed from where the airplane let out the sound, where the observer is, and where the airplane now is. If you double the height of the airplane then that becomes a similar triangle with all lengths doubled. So we may as well assume that the sound traveled for 6 minutes, so the plane has moved 50 miles and the sound moved 76.
It is easy to verify that at any point in time the rate at which the airplane is adding to the angle between where it was and where it will be depends on how close it is to you (the closer the better). From this it is easy to show that the maximum has to happen with the original position of the plane, the observer, and the current position forming an isosceles triangle. And that happens when the observer, the half-way point for the plane, and the current position form a right-angled triangle with opposite 25 miles and hypotenuse 76 miles. So the adjacent is sqrt(76^2 - 25^2).
The rest falls out of the definition of atan2. (Assuming no careless errors.)