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Although standard mathematica notation glosses over the difference, it's important to distinguish between the following two versions of the power operation, which I'll call pow1 and pow2: pow1(x, y) = x^y where y is any integer pow2(x, y) = x^y where y is any real

The value of 0^0 is 1 for (pow-a) and 0 for (pow-b).



But lim x->0 (x^x) = 1. Why should 0^0 be 0 then?




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