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on Feb 13, 2014
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Massively multiplayer online Flappy Bird
Let distance between ground and top of screen=100. Bird position after a flap at y=y0, time=t0:
y(t) = y0 + 13.8 - 147 * (t - t0 + 0.288)^2
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y(t) = y0 + 13.8 - 147 * (t - t0 + 0.288)^2