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jacquesm
on Dec 18, 2012
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Why 256 bit keys are large enough
Doesn't halving the search difficulty mean dropping 1 bit from the key length? So 256->255 rather than 256->128?
scott_weber
on Dec 18, 2012
[–]
The numbers are correct, but it was written in an odd way. Grovers algorithm gives a speedup of sqrt(n), so the exponent gets halved.
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