On: If i = 0, why is i += i++ 0?

[krob]

this is correct. i = 0; i+=i++;

(0) + (0)++ = 0 next time around (1) + (1)++ = 2

[yen223 → krob]

Unfortunately this is not correct.

If you run

  for (int x = 0; x < 10; x++)
  {
    i += i++;
    Console.WriteLine(i);
  }

i is always 0.