Consider the "calculation" for ai_unified for an uncharged case:
L_src = m hbar / (c*mp^2).
Expand and simplify and get L_src = m G / c^2
L_lim = w * L_src = 2 m G / c^2. Also the value of rs.
metric_factor is irrelevant, as both ai_gr and ai_unified are divided by it since L_lim = rs
ai_unified = (c^2 * L_src) / (radius^2 * metric_factor). Expand L_src and get ai_unified = m G / (radius^2 * metric_factor)
This is IDENTICAL to the formula used for ai_gr when there is no charge. Presenting "0% difference" like it is a result is sloppy ignorant bullshitting at best and deliberate fraud at worst.
The calculation uses m_p , which is independent of G. Deriving G to 8 ppm from m_p is not necessarily "meaningless", or at least it's statistically non-trivial. It is not just "G = G".
You mention the "uncharged case", but ordinary matter is not mathematically neutral. By focusing on the uncharged case only, you ignore that this is an attempt at unification. The model proposes that geometry explains both interactions. You cannot remove one of them, because in nature they happen at once.
The rest of your remarks don't seem "uncharged" at all, but the opposite.
You mention the "uncharged case", but ordinary matter is not mathematically neutral.
YOUR CODE assumes that it is, when it passes "q": 0 for four of the six objects.
For the other two, it passes "q": 1. Let's look at what it does then:
L_src is much much smaller than Le, by roughly a factor of (mass / mPL)^2
The calculation of lambda_a uses the electron mass even when calculating for a proton
For the given objects, metric_factor is negligible.
ai_unified = c^2 * (alpha * hbar / (me_kg * c)) / r^2 = alpha * (hbar * c) / (me_kg * r^2)
but alpha = k*e^2 / (hbar * c)
so ai_unified = k * e^2 / (me_kg * r^2) + small correction of O((mass / mPL)^2)
That's exactly the formula used for acc_coloumb in the code. Also interesting to note the "Coulomb acceleration" for a proton is calculated by dividing the electric force by the mass of the ELECTRON somehow.
As for "Phase 2"? The program's output doesn't even agree with the implementation about the formula being used.
Hm. You are correct about m_p and m_e. That is indeed a sloppy mistake in the script. Bad code. However, the hypothesized closed value of G stays the same.
Consider the "calculation" for ai_unified for an uncharged case:
This is IDENTICAL to the formula used for ai_gr when there is no charge. Presenting "0% difference" like it is a result is sloppy ignorant bullshitting at best and deliberate fraud at worst.