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Big O Notation omis constant factors that tend to be significantly larger for log-n algorithms.

I think he talked from personal experience.





Could be. But very poorly stated if so.

Anyway, I do not think that even "typically" such statement can remotely be truth. It is 2 orders of magnitude away (20 to 5000).


True, but it wouldn’t be unthinkable. Especially if the O(n) algorithm accesses data sequentially and the O(log n) has indirections.

But maybe the author simply made it up.


You are all right. I was wrong. Should not post math just before going to sleep… So, let’s make the same mistake first thing in the morning:

x=20log2(x) at 143

https://www.wolframalpha.com/input?i=x%3D20*log2%28x%29




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