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Images reveal exocomets around nearby stars (skyandtelescope.org)
100 points by gmays 4 days ago | hide | past | favorite | 22 comments





It's a neat result, its maybe a bit to specify sizes. At least with the images provided in the article, they're getting maybe:

10 pixels, across across objects of >1 astronomic unit (149,597,870 km). If those rings are like our own Kuiper belt objects, then those are more like 25-50 AU. If they're like the asteroid belt in the inner solar system, then maybe 2-5 AU.

If those are images from the nearest 74 solar systems, then those are somewhere from 4 ly to 20 ly away (~4e13 km to 2e14 km away). [1][2] They're probably further away.

Based on the stated resolution, ALMA is supposed to get ~10 milliarcseconds (10−7 radians) resolution. [3] With the small angle approx. that means it can resolve:

  (~4e13 km to 2e14 km) * 10^-7
   = 4e6 km to 2e7 km
   = 0.025 AU to 0.125 AU
It's cool though, as it at least implies disc path clearing, orbital harmonics resulting in ring formation, and probably a lot of other implications. Likely gives excellent regions to try looking for further planets, planetoids, or planetesimals. Provides some idea of how likely it is for the conditions in our own solar system to cause similar formations in further away solar systems. Mostly a lot of single rings, not that many double ring groups. Quite a few that end up looking more like bloby clouds.

[1] 100 Nearest Star Systems, http://www.recons.org/TOP100.posted.htm

[2] GJ 1005 (#74), https://en.wikipedia.org/wiki/GJ_1005

[3] Atacama Large Millimeter Array, https://en.wikipedia.org/wiki/Atacama_Large_Millimeter_Array


Someone once broke my brain about hostile alien movies. They said if the aliens were here to take, they could stay in the Oort Cloud or outer planets where the gravity well is shallow, and strip mine our system for natural resources and we wouldn’t even be able to throw anything that high to stop them.

We could just watch and shake our fists as they steal our future at their leisure. They wouldn’t even have to send their people. They could use robots on ten systems at once.


The first valuable thing on Earth is life. Life may be rare enough, or diverse enough, that worth sampling the unique life on Earth. The intelligent monkeys can be useful, but can be knocked down is cause problems.

The second valuable thing is intelligent life. The intelligent monkeys are worth preserving and talking to. But their advanced civilization has lots of potential dangers so need controlling protectorate.

The third valuable thing is better minerals. The active processes of the Earth concentrates minerals. They could grind up a whole asteroid, but cheaper to take from Earth. Also, biologic processes make minerals; vacuuming up coal is cheaper than making it. These wouldn't be whole civilization but pirates grabbing some cheap loot before the authorities and natives notice.

The fourth valuable thing is Earth itself. Inhabitable planets are rare. The expected way would be apocalypse or annihilation. But I think it would be more interesting to have alien invasion where they ignore us. They settle the arctic, and don't do anything until attacked. Then they start removing CO2 until the temperatures drop and ice age returns.


> we wouldn’t even be able to throw anything that high to stop them

Worse, they could throw bits of the Oort Cloud at us.


It takes just as much ∆V to throw a rock from the Oort cloud to Earth as to throw the same rock from Earth to the Oort cloud. The aliens don't get an energy advantage by holding the high ground.

> It takes just as much ∆V to throw a rock from the Oort cloud to Earth as to throw the same rock from Earth to the Oort cloud.

Yes, but they clearly have the capability to get to the Oort Cloud, and we (other than a small probe) do not. Having the high ground (both physically and technologically) makes holding the Oort Cloud a pretty good spot to be in.

(It also takes substantially less ∆V to nudge an existing rock into a nastier trajectory, and we're essentially a big easy to hit static target.)


That's not actually true; it's an asymmetric problem. You're asking about impacting another orbiting object with nonzero relative velocity. That's not the symmetric question of transferring between two orbits A and B, both ways; it's the asymmetric question of going from orbit A to "some orbit that intercepts B at some point".

It's much less delta-v to go from the Oort cloud to Earth—to a highly-eccentric orbit that intercepts the Earth's orbit, without matching its velocity.


No it doesn’t, at all.

The whole point of the high ground is someone just needs to ‘drop’ something in, which is cheap and easy, but someone on the ‘low ground’ needs to make up all the energy to get up there before they are even at the same level.

The energy involved in de-orbiting something and dropping it to the surface of earth (at very high speed) is orders of magnitude less than it would take to get the same mass to even earth orbit from the surface.

Holding a brick over the opening of a well is a much more credible threat to someone at the bottom, than that someone with the same brick threatening to throw it back out.


That logic doesn't apply to orbital mechanics. The atmosphere is used to brake when satellites are deorbited.

Huh?

All you need is for orbits to intersect with the surface, not for a zero velocity vector at the surface. That is far cheaper to do than getting to orbit in the first place.

This absolutely applies to orbital mechanics.

Atmospheric braking makes it less likely to punch a hole in a skyscraper in manhattan when de-orbiting. And defacto raises ‘the surface’ in some senses.

It doesn’t change that it’s far ‘cheaper’ to go down a gravity well than go out of one.

Though that atmospheres (and liquid oceans) exist at all does prove exactly the point that I am talking about. The Sun and planets too, come to think of it.

If it was cheaper to ‘get out’ than ‘fall in’, none of those could exist.

Edit: I used a Hohmann transfer orbit calculator, and from an orbit of ~200km above sea level to an orbit intersecting ground level (0km), it only takes 203 m/s.

Without an atmosphere, it would be quite a show of course. But in this situation, that’s the point isn’t it?


Yes, I guess you're right, you aren't going from orbit to orbit, you only try to crash something (and actually want to keep the difference to create an impact).

Still, your logic doesn't apply, and hitting something in a higher orbit shouldn't be that much harder. You also only need to nudge it to hit something UP. (though it does get harder with a lesser impact with increasing distances)

I fact there might not be that much of an effect at all when you consider that both Earth and the Oort cloud are in the Sun orbits - you would have to hit something pretty hard in the Oort cloud to create a massive impact on Earth, there would at best be a bit of leverage, which I guess wouldn't outweight the protective effect of Earth's atmosphere, unless you try to send something monumental, at which point you probably can just come down and hit Earth. Consider also the timescales involved.


You might want to do the actual math.

Did you do it? That maneuvre would take decades to millenia, and when you use something that far, it may be more efficient to push it into a retrograde orbit so that it hits Earth heads on, instead of chasing after it. It's just absurdly impractical.

Anyway, if you really want to destroy a planet, you want sonething small but fast. It penetrates into the planet, and rips surface on the other side.


Read my comment. Yes I did. Time was in the hundreds of hours.

Dropping things is way easier than throwing things up. This is easy to verify yourself too.


You fundamentally misunderstand the concepts. The other poster is correct. Given two orbits, it takes just as much energy to get "up" as it does to get "down".

care to provide some math? delta v calcs quite definitely disagree. no one is going to LEO on only 220 m/s. assuming an impact with the surface of course, which is clearly part of the equation.

if landing gently, then sure. but that is an entirely different problem.


When you’re standing at the bottom of a well, don’t mouth off to the person standing at the top.

I always thought that comets come from the Oort cloud, but apparently short-period comets come from the Kuiper belt or its associated scattered disk—similar to the exocometary belts in these images.

I always wonder. If we theoretically could know for each photon the direction vector and distance travelled, then could we make a collector that could image an exoplanet? Or is this simply impossible?

We actually already have multiple images of exoplanets. [1] and [2] were both taken with the Very Large Telescope in Chile. Granted, you can't see much beyond reddish blobs. But they are not that much worse than Hubble's images of Pluto [3].

We probably can't do much better with earth-based telescope arrays due to atmospheric distortions. But with satellite launch costs coming down we will see large telescope arrays in orbit in a couple decades, and those might do a lot better

[1] https://science.nasa.gov/resource/2m1207-b-first-image-of-an...

[2] https://www.eso.org/public/images/eso2011b/

[3] https://esahubble.org/images/opo1006h/


Doesn't that practically guarantee Exoplanets in those systems?

The article says we already knew that:

> astronomers knew disks of debris leftover from planet formation were common around newborn stars

The new result allows much more insight:

> only a few have been resolved in sufficient detail to study their internal structure. “This is the first time we can make a statistical analysis of what’s going on in these disks,




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