One problem of ipv6 is proponents saying there are 2^128 addresses.
It's really hard to comprehend how many unusable ipv6 addresses are.
Having more than 2^16 hosts on a subnet is pretty much impossible. Sticking with "grain of sand" units, but using volumes all from wolfram alpha:
There's 2^80 usable IPs in the entire ipvv6 space, because of the /64 subnets. That's plenty. But for every subnet, that's 40 cubic metres unusable for every subnet, and a sphere 1mm wide of usable addresses.
My ISP give me a /48. I have under 30 addressable devices over 3 vlans. I'm using 40 cubic miles of space. A ratio of about 10 trillion:1
But that's nothing. The IP allocators are happy to give a bank a /16, or in your "grain of sand" measurements 30 times the volume of the moon.
To match my unused:used ratio of 10 trillion to one, chase manhattan would need 2^70 devices, which is billions of addresses per cell.
All the space that fanboys go on about is almost all unusable, so the extreme examples don't really help at all.
It's really hard to comprehend how many unusable ipv6 addresses are.
Having more than 2^16 hosts on a subnet is pretty much impossible. Sticking with "grain of sand" units, but using volumes all from wolfram alpha:
There's 2^80 usable IPs in the entire ipvv6 space, because of the /64 subnets. That's plenty. But for every subnet, that's 40 cubic metres unusable for every subnet, and a sphere 1mm wide of usable addresses.
My ISP give me a /48. I have under 30 addressable devices over 3 vlans. I'm using 40 cubic miles of space. A ratio of about 10 trillion:1
But that's nothing. The IP allocators are happy to give a bank a /16, or in your "grain of sand" measurements 30 times the volume of the moon.
To match my unused:used ratio of 10 trillion to one, chase manhattan would need 2^70 devices, which is billions of addresses per cell.
All the space that fanboys go on about is almost all unusable, so the extreme examples don't really help at all.