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> Amateur math prodigy? Bored puzzle enthusiast? Aspiring Troll? Who knows.

Who knows, indeed.

> will that have the effect of increasing or decreasing government/big tech ability to control and manipulate people?

I'm so confident that you don't have this that I would bet literally any amount against (if I was a betting man.)

The real answer is that there would be chaos. There would be some wars, there would be some pockets of stability, and the most entrenched powerful people would carry on as a new order re-formed below them. Old money and vertically integrated megabillionaires would watch from perfect safety as it all unfolded.

For most people on the planet, they'd be plunged into a well of uncertainty, chaos, and violence, find a new normal in the end eventually for whoever survives the upheaval. Then a new generation will be born whose parents will tell them what tiktok was like back before the bombs fell.




The silver lining is that OP may solve a Millenium problem along the way, which would net them $1M of then worthless money.


Nope, no millenium prize solutions yet. Nobody pays for proof of Goldbach's now, and i HATE the "submit your work and we Might pay you years down the road."

I'm trying to get paid the old fashioned way, on ebay. If you want to get rewarded for something, the last thing you should do is give it away to the public, never mind the security issues involved. You can check my other reply if you want to see the description of the basic model for attacking the problem, in the ebay listing. It turns out that the model is applicable to both one-way functions. I didn't realize that up front. Most likely some have already figured them out.


It's easy enough to prove that you can do it without revealing the method. E.g. try factoring

828779882149581516608371895000952095542845654164714667404503828622425254433342333212851597308609571788866517548728051290486514664536526513189610109365786163329028919611934048763953195663095107461374317207248372551320318065286778764851524374520963310255832610228096092786871242729401067756589198807809654636897168275783949053564041346551042535096866922015555150328851789814755353416970423293384462938529229504776847343483500413283766835786156833770930672918554267754213460743282944441316468046663307327275988621784143792477230074308093417024020208503042995610623838662249568686237622629268718158351345829871048206694289429425274539851662996156137399085654359584771983891913824833817853560160370503998066766467250804875540795977735547426031658244875845477862785702453425686697408010169925029349599361158016358703937995386113446794769936324484430612916057117051719218218325916643485253731482150206366098004386513239730239094402800085867574268581700189625680138287068263081046491346243525955935799560535151953302697995913599546972232450859613369273247939285956354820615032954994533035265826732005181461819339324028400499227345113535895172348378848646216279768426623149666406923929418315334152487496960069280408337431573225747461462095889

which I created by multiplying two primes generated by openssl prime -generate -bits 2048


If you are a qualified buyer, and want to pay at least $24000, you can take one of the methods and check it yourself (there are more than one, but work on same principle). I don't put the algorithms in computers, so any checking above a 9 digit product will have to be done by someone else. There is enough of a clue in the ebay description to figure it out yourself, maybe. It seems obvious to me since i already know the answer. I assume now that capable mathematicians can make the connections much faster than i did. Let me know if you figure it out and factor your test number quickly. Then again, i really don't care if you do, which I'd bet all my money and yours too that you won't figure it out.



Hehe, thanks, I'll pass. But good luck.


I've got to admit, I've been NerdSniped by this one. I've been putzing around in Python for hours now.

Factoring large numbers always sucks me in.


Play with it, and you may just figure it out. I'm glad someone gets something interesting out of my posts.


Ok




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