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For people wondering about the hourglass problem: 1) @0min: Take both glasses (4 & 7) and flip them over. 2) @4min: When the 4min glass is empty, flip it back over 3) @7min: When the 7min glass runs out, flip it back over. 4) @8min: when the 4min glass is empty, there will be 1 minute in the 7min glass. Flip the 7 glass. 5) @9min: When the 7min glass runs out, you will be at 9min.


Reminds me of the water puzzle in Die Hard 3.




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