You can certainly use generic parameters in methods—the [T any] just has to be on SomeNonGenericType, even if it's not used inside the type itself https://rakyll.org/generics-facilititators
Yes, but that's completely different thing. If you move T you would change the semantics.
- func (self SomeType[T]) Foo(...) is a method for a class parametrized on T. So if you want foo.Foo(1) then it only works for foo that's SomeType[int]. You cannot then easily call foo.Foo("one") on the same instance.
- func (self SomeType) Foo[T any](...) - if that'd be a thing - would be a generic method on SomeType that works for any T. So you can foo.Foo(1) and foo.Foo("one") on the very next line and that would work.
You can instantiate it with [any] then use whatever you'd like https://go.dev/play/p/JeSuB_xYNEf, but I don't think it would work with a type constraint such as `int|string`, which would be a fair point.
Sure, but it's no longer generic, you're just using runtime types again.
This is extremely important, because it means `func (someType[T any]) foo(T x) T`, `x.foo(1)` would return `any`, not `int` like a generic function would.
In fact, if you're going to instantiate a generic type parameter with `any`, I would very much doubt you wanted a generic type in the first place.
Oooh. My bad. Thank you! I honestly thought that wasn't possible at all. Today I learned.
However, it won't work for return values, right? Because e.g. `func (some something[T]) hi(b T) T` would return `any` and not whatever it was provided (`int` or `string` respectively).