Does that mean this: Array(n).fill() is a permanent deoptimization? And if so, i... | Hacker News

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eyelidlessness on Nov 1, 2021 | parent | context | favorite | on: Sparse vs. Dense Arrays in JavaScript

Does that mean this:

    Array(n).fill()

is a permanent deoptimization? And if so, is the new array returned by:

    Array(n).fill().map(x => x)

better optimized (after the, presumably, suboptimal iteration)?

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