Hacker News new | past | comments | ask | show | jobs | submit login

Alright, but the principle still holds:

You have some action act(x,y). The encoding in the bitstream can either differ for act(x,y) or act(y,x) or it is the same.

The original article states that the effect of act(x,y) and act(y,x) is the same. But the bitstream may differ. So it is commutative in the operations of the computer, but not in the bitstream instruction.




Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact

Search: