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cokernel_hacker
on May 5, 2020
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Floating Point Visually Explained (2017)
Interesting. One issue is treatment of 1 / -inf. This would be -0 in traditional IEEE 754 but would now be +0 IIUC.
This would imply that 1 / (1 / -inf) would now be +inf instead of -inf.
thechao
on May 5, 2020
[–]
0 is unsigned. I would reject 1/inf — it would be NAN. If the user wants to play silly games with derivatives, computer algebra systems are that way: —>.
piadodjanho
on May 6, 2020
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NaN is NaR (not a real) in posit notation.
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This would imply that 1 / (1 / -inf) would now be +inf instead of -inf.