From your description, I fail to understand how does it depend. You're saying that the algorithm is wrong, and changing the type doesn't help. If the type is not the issue, what difference does it make?
and B uses naive summation then you can expect the end result of A to be more precise than the end result of B – even though both algorithms are correct.
> and B uses naive summation then you can expect the end result of A to be more precise than the end result of B – even though both algorithms are correct.
Formally speaking, no. The problem can be defined precisely. At least one of the algorithms fails to solve the problem.
In practice of course, some amount of error may be acceptable.