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darkmighty
on Aug 18, 2015
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An Argument for P=NP (2005) [pdf]
Ah that's interesting, ill read more on those. But did we just come back full circle and the existence of strong pseudorandom generators depends on P!=NP? :P
( P!=NP => BPP=P => P=BPP!=NP ?)
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( P!=NP => BPP=P => P=BPP!=NP ?)