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Establishing the Rust-Python FFI (wafflespeanut.github.io)
33 points by wafflespeanut 686 days ago | hide | past | web | 3 comments | favorite



I have recently been writing a Rust FFI for (an obscure dynamic array-language) Q. Unlike the OP, I didn't do it for speedups - in fact my Rust code is no faster than native Q. However there are other reasons to write FFIs - to benefit from Rust's extremely powerful type system, which can all-but-guarantee a program's correctness.

For example I recently spent a fortnight trying to write a parser for a complex binary file format in Q, but the dynamic typing got in the way. I would constantly find that some invariant would get broken without my understanding how, and refactoring was a matter of "change this here, run until it breaks, then fix, repeat". Eventually I gave up and rewrote in Rust. It took the same amount of time but the implementation is rock solid and I am confident that it won't ever crash and that e.g. malformed data will be identified and handled correctly.

I am now getting into the habit of reaching for Rust whenever I get bogged down with another language - it makes everything else seem brittle and slow.


Maybe it is just me, but whenever I come across a type as ugly as * const * const c_char I would create a type alias. That way I can remember what it is a month later. Would this work in Rust?

    type c_str = *const c_char
    type c_str_arr = *const c_str

    pub extern fn get_stuff(array: c_str_arr, length: size_t) -> c_str {...}


Yes, that exact code would work, except with some extra semicolons.




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