Replying to myself: all those sides would be of equal length, defying Eculid -- ... | Hacker News

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e12e on June 3, 2013 | parent | context | favorite | on: Hexagonal grids for games

Replying to myself: all those sides would be of equal length, defying Eculid -- or rather I'm missing the fact that five triangles meet in the original icosahedron. So those "corners" would be pentagons, not hexagons.

lmm on June 3, 2013 [–]

Indeed that is one way to derive the same "football projection".

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