Can you solve it? The Greplin programming challenge 220 points by rwalker on Oct 8, 2010 | hide | past | web | favorite | 156 comments

 Seems like I may be the only person to have used a bioinformatics approach to the first problem! bl2seq to the rescue!! I'll explain my approach if anyone seems interested... as I am not sure if posting solutions is acceptable here.Edit: As others seem to be posting gist/snips etc. so I guess it is OK.Step 0 - Copied parent string to file: p1.txtStep 1 - Used python to reverse the entire string and copy to second file: cat p1.txt | python -c "print raw_input()[::-1]" > p2.txtStep 2 - Formatted the two files, so as to be parsed as FASTA, by adding sequence name headers.Step 3 - Use bl2seq (blastp) locally or online to align the two "sequences". Final alignment shows only one major chunk of identity, i.e. the answer.So, in essence, a dynamic programming algo would work.
 If bl2seq gets the longest common subsequence I did exactly the same thing. In haskell it just seems the right thing to do. Actually it would be damn interesting to see if there are patterns in the solutions for every programming language.
 "Even if you're not looking for a job, we'd love to hear what you thought about the challenge."I would be curious how many people did you lose because of phonecall requirement (before you changed it).Also CSV for just a list of 22 numbers wasn't really necessary.If you do web puzzle, the best is to keep everything self-contained, no downloads, no using external channels, just copy and paste.FYI another Python cheater here (+Wolfram Alpha & Wikipedia, I'm lazy :).
 I just copied the CSV into the text editor. But I just realized how stupid I was. I wrotevar nums = "3, 4, 9, 14, 15, 19, 28, 37, 47, 50, 54, 56, 59, 61, 70, 73, 78, 81, 92, 95, 97, 99".split(", ");for(var i = 0;i< nums.length;i++) { nums[i] = parseInt(nums[i],10); }Instead of just editing the numbers so that it was an array right away. Happens if you code before you think :-)
 I don't think trivializing the combinations with Python's builtins, looking up the fib primes with OEIS, or computing factors with Alpha is cheating. I hope, in fact, it's the whole point of the exercise: choose the right tools for the job. If you're writing code to test primeness or generate Fibonacci numbers, I sure as hell don't want to hire you.
 If you're writing code to test primeness or generate Fibonacci numbers, I sure as hell don't want to hire you.Maybe you should have called it the "Greplin Challenge," then, instead of the "Greplin Programming Challenge." It's not a real task, after all; the reward comes from accepting a completely artificial challenge. I'm going to do the challenge before dinner tonight, and before I leave work I could get source code for the solutions from the guy down the hall from me who did the challenge as soon as it was posted -- and you certainly don't want to hire a guy who recodes other people's work for no reason, right?
 Maybe we have a different hiring mindset than dschoon - we're equally happy with people who find the answers or create the answers. In a production system, we certainly wouldn't want hand-rolled primeness checking. But in a programming challenge, we think it's fun to write it for yourself.
 Oops; I wrote my comment under the assumption that dschoon was with greplin, and in retrospect I'm not sure why. Sorry about that.
 Code to generate fibs is literally one line. Remember eigenvalues :)?
 Sorry, couldn't help myself!! That approach is just so damn elegant.int((1/math.sqrt(5))*(math.pow(((1+math.sqrt(5))/2),fibonacci)-math.pow(((1-math.sqrt(5))/2),fibonacci)))
 Elegant, but inefficient if you want to get exact values for large n. You're much better off using doubling operations. If you forget those, you can remember them from the matrix version. If fib(0) = 0. fib(1) = 1. etc. Then`````` n [0 1] = [fib(n) fib(n+1)] [1 1] [fib(n+1) fib(n+2)] `````` With repeated squarings, you can efficiently generate any Fibonacci number you want.
 Here (where you have to search through Fibonacci numbers) I suspect memoization is rather the way to go:`````` # memoized fibonacci function fibtable = {1:1, 0:1} def fib (n): global fibtable if n in fibtable.keys(): return fibtable [n] val = fib (n-1) + fib (n-2) fibtable [n] = val return val``````
 There is no need to keep track of all previous values.`````` last_fib = 0 fib = 1 while fib < 225000 or not is_prime(fib): last_fib, fib = fib, last_fib + fib``````
 I wrote extremely naive Ruby algos from scratch that solved the problems in a couple seconds, or in the case of the last problem, a couple of minutes. I'm sure the whole challenge would have taken longer if I tried to use any dependencies.
 I tend to agree with dkarl here because if it was for real, I would just have looked here to find all the answers and maybe the passwords.It was way more fun to do it from scratch :DThanks grepplinp.s. the csv was copied in my [] python list :)
 I think this would've been a better filter for hiring if the magnitude were larger (e.g. huge string, more numbers for the combination, etc) or if there was a strict time limit. As it is right now, I don't think the hardcore hackers you're looking for will be that enticed.
 I think that you'd be surprised at the sheer number of applicants a very basic programming challenge can weed out. The company that I work at has a simple test to parse a csv file and a surprising amount of people who appear to be good candidates bomb it.
 Do I get bonus marks for solving this without writing any code?
 I immediately went to Wikipedia, found out what type of CS problem the first challenge was, then followed the external links at the bottom of the page to find the Perl module I needed and installed it from CPAN.I quit because this seemed like cheating but now I'm thinking... Maybe it was the point? To see if I would try to find something off-the-shelf to solve the problem quickly. Still not sure it was, because if so the challenge certainly doesn't demonstrate that I have any CS chops. :-\Spoiler alert: I believe this module will do the trick http://search.cpan.org/~gray/Tree-Suffix-0.21/lib/Tree/Suffi...
 Easy job for a regex:`` while (\$string =~ /((\w+)\w?(??{reverse \$2}))/g) { print "\$1\n"; }``
 fuckin nice. now I feel like a doofus for using ruby, when I thought it was straightforward.
 I've done it ruby this way:`` text.scan(/(.)(.)(.)(.)(\3)(\2)(\1)/)``
 That's pretty frail. It won't catch palindromes with an even number of letters (e.g. ababbaba) and it'll only find those of at most 7 characters. Granted, you can use those matches to work outwards and search for more, but I didn't think the general solution was all that hard.Oddly enough, it didn't even occur to me to try a regex and I like using them quite a bit.
 I didn't solve the problems using existing code either. All three are entirely solvable by pencil and paper (or just inspection in the first case).
 How do you go about solving #2 on pen and paper? Well, calculating the Fibonacci sequence, ok. The sum of prime divisors of X+1, I guess... though it gets slightly harder for me after dividing by 2, 3 and 5. But how do you know for sure that X is prime?Based on bd's link, I'll just assume that you have super powers. (or I'm approaching the problem the wrong way)edit: I was starting to think about what to write for #1, but ended finding the answer by looking at it as well.
 You can use the Sieve of Eratosthenes to generate primes with pen and paper very easily. Or, you could find a roll of paper and evaluate any computable function (assuming unbounded paper). ;)
 It doesn't seem to make it especially easy: you still have the same problem of having to eliminate the multiples of 61, 79, 89, etc. which are not obvious. Yes, you can count, but it looks very time-consuming.The problem still stands that one needs to go in the 500,000s for that problem (thus 700s for the square root). That's still a long way to go…I'm really curious about how cperciva did it. You're supposed to find the first Fibonacci prime over 227,000. The first Fibonacci number over that is obviously not prime (multiple of 3), but the one after that is not obvious even if you have the list of primes obtained with that method.
 You have less than 30 Fibbonacci numbers to compute.That 317811 is divisible by 3 is obvious upon adding its digits together.Once you've verified that 514229 isn't divisible by a handful of small primes, you don't try to prove primality. Instead factor 514230 and stick it in. After dividing by 2, 3, and 5, you've got 17141. It doesn't take that long to run through 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59 and 61. At which point you have an answer you can try plugging in to discover it is correct. Which is a sequence cperciva pretty definitely has memorized. (I do.) Or alternately cperciva may have better factorization techniques memorized.If you already have a routine around for factoring (I do), then this takes longer than coding it. But I could do it with paper and pencil pretty easily.
 Fair enough. Though I'd argue on "entirely solvable by pencil and paper", since the answer is an educated guess in that case and the proof that it's correct resides in checking with the webpage. ;-)To be honest, in the same amount of time, one could also estimate the range where the answer should be and plug it one by one in the form until it validates. (which we'll call a less educated guess :))
 I would think that pencil and paper would be slower than writing the programs. But you're right that they are ridiculously easy.
 For the third problem, yes. But after solving the first two problems without writing code, I didn't feel like starting on the last problem.
 I seem to recall that there were 2^22 sets in the power set of that list of numbers, so you obviously had to use some kind of technique to cull the vast majority of the sets.Hmm... now that I think about it, did you do something like starting at the end of the list, then subtracting numbers as you went until you either found a set that added up to your top number, or found it impossible for that number to be in the set?It seems like it would take a lot of paper to do that, but it's more efficient than the simple brute force technique I did.I'm just curious, because I bet there are better ways to do that one and I think the challenge is probably over by now.
 Here is a hint. Look at http://en.wikipedia.org/wiki/Pascal%27s_triangle and ask yourself why the 23nd row can be calculated without explicitly enumerating all possible subsets.I'm pretty sure that cperciva used a similar trick, but in each row you're potentially adding another element of the set, and not potentially adding 1.This gives you a mapping telling you how many ways there are to get 0, 1, 2, 3, etc as the sum of some subset of the set. Just sum this over the set, and subtract the size of the set. (Every element in the set is the sum of itself, but you don't want to count those.) And there is your answer.
 Ah. Well I'm an even worse hacker than I thought!
 Don't feel bad, it's just how cperciva rolls :)
 Wow, I strongly recommend reading this (or, better yet, the full back-and-forth leading up to it: http://news.ycombinator.com/item?id=35068 ).I wish I had discovered HN back then.
 I solved all three problems in under a half-hour by writing quick-and-dirty Java programs to do it. The standard libraries provide almost everything I needed; the only thing I used other than that was Maple to factor the number. I'm pretty sure mucking around with CPAN libs such would have taken me longer. Granted, my solutions were brute-force and not very elegant, but for simple problems like these with small inputs I can write code to solve it faster than finding the answer elsewhere.
 Writing code for 2 & 3 would probably take more than solving it with pen&paper, for me at least. I wrote code for #1 because it was practically 3 lines..If it was really meant as a programming challenge, it should feature problems which are worth writing code for.
 I'm disappointed that it is possible to solve by hand, as that undercuts the reward. This is one of the great aspects of ITA's programming problems: none of them are even solvable by brute force.
 I didn't know that was within the extent of your powers cperciva
 Now I have to try this.
 Were you actually satisfied after doing that? You probably just wasted your time.
 Nice and short Haskell solution to #3: http://gist.github.com/617675Ruby solutions to #1 and #2: http://gist.github.com/617676 http://gist.github.com/617678
 Nice, but don't compute the length of a list if you don't have to.(not . null) instead of (\x -> length x > 1) is shorter, and works on infinite lists also.Edit: well, in case you would test for x>0.
 That was fun, good waste of time while my code was compiling. I just used C++ and hacked up a prime seive for #2 and for #3 used a combination generator I had previously used before - http://photon.poly.edu/~hbr/boost/combinations.html
 for #3 used a combination generatorCongratulations, you just used an exponential-time algorithm for a polynomial-time problem.
 Congratulations are in order, he sacrificed 400ms CPU time to save at least a few minutes of coding time.
 I wasn't being entirely sarcastic. It never occurred to me that you could use a non-polynomial-time algorithm.
 All the solutions posted here seem to involve generating all subsequences. Could you say more about your approach?
 Not always is "exponential" a bad thing. For small sets, the expo algorithm is actually faster than the polynomial one. Although yeah, generally speaking, it's a bad idea.
 I tried on #3 the most inefficient algorithm I could come up with - blindly going through all possible combinations and checking if their biggest member is equal to the sum of the rest. Time of the execution: 0.6sI am not sure if this step of allowing the "shortcuts" was part of the game or not. All that would had to be done is to give 128 elements of the array to exclude at least the most blatant brute-forcing.
 I'm usually pretty bad at these kind of challenges (lately I tried registering at one mind-challenges site, but I couldn't even get past the five entry-level questions, which would have allowed me to even register), but this was surprisingly easy. Simple brute-force methods worked for each of the three tasks. I was totally surprised that the first time I entered the answer for each of the tasks, it was indeed the correct one.But then again... these are all pretty standard computer science problems, nothing that I hadn't in some way done before.On a side-note: Interestingly I used recursion for each of the three problems. Well... actually for the primes-problem I got stack overflow and rewrote it to not use recursion, but still, at least in principle :=)
 Agreed - I was laughing as I was writing some of my code because it was so bad. These sort of questions are designed around algorithm design, but a one-off problem with these small of sample sets doesn't need an elegant solution - a hatchet job does just fine. I'm not a CS grad and my math skills are a bit iffy, but I was able to solve all three challenges in a pretty reasonable amount of time.
 Uh ... call a phone number? No thanks.Edit: Excellent! Back to hacking.
 Phone call no longer required.For what it's worth - it's just a Twilio app - we thought it would add to the fun.
 I'm curious to know why calling a phone number was a deal-breaker.It seemed eminently likely (to me) that it would be an automated system, but, even if it wasn't, talking to someone isn't that big a deal to me. I certainly wasn't concerned about long-distance charges, but I suppose that might be a problem for some.I thought it was a nice little twist in the problem set.
 but, even if it wasn't, talking to someone isn't that big a deal to me.A lot of people struggle with the phone. I certainly have, though I'm getting better at it. I've noticed many people become spookily compliant on the phone, endlessly listening to and being polite to even the most annoying callers instead of just hanging up.
 I live in Norway, so the phone bill is a significant factor. Also, the wife and kids are sleeping in the next room, which would require me to step outside on the porch in the middle of the night with my cellphone.Yet also, I'm so tired I couldn't have englished very well in my phone anyway. :-)
 Maybe you don't want them knowing your phone number to call you back with job calls or whatever. (Of course, there are ways around that too.)
 I'm hearing-impaired.
 Yep, decided not to continue when I got to that point.It looks like the number is a landline in the Bay Area. I wonder if some poor soul at Greplin will be taking calls all day.
 Perhaps this is one of those "secret recruitment processes."
 Oh my god, Haskell is so pretty. This is the first time I've used it to solve math problems. Is it kosher to share solutions?
 I gist'd one because I saw others sharing. I'd be curious to see how you did things in Haskell.
 Damn, I have to go in to work early today or I could continue this. The first one only took a minute or two of coding to solve in Perl. The search string was several times longer than my code, even with use warnings & use strict in there.I'd write a bit of code to memoize the function before I'd do the Fibonacci numbers, though, and I just don't have time to continue right now, even though it's pretty easy. Are the rest of the tests like that? Do they force you to use more efficient code, rather than simpler brute force tests so that your code has a decent runtime?
 brute force seems to be sufficient
 you also probably don't want to memoize, you aren't going to re-use, so why waste the memory?
 I wrote that right before leaving for work, so I hadn't spent any time thinking about the problem.Coming back, I see that I really don't need to be very efficient for any of these problems, which I honestly find a little disappointing.
 So what languages did everyone use?I decided to try a different one on each level, so I used Python, bash (letting GNU coreutils 'factor' do the hard work), and Haskell, respectively.
 JavaScript. I had my browser open ... it seemed like the logical place. :)
 Common Lisp of course :-)
 I used Haskell for the first one (was my first actual Haskell program, everything before was just xmonad config), C for the second one (already had the needed code for generating fibonacci sequences and a prime number sieve from when I went through the euler problems using only ANSI C) and Perl for the last one. I initially used Data::PowerSet for the Perl code, but decided to write my own after it took several minutes to build the combinations and I discovered that I had the wrong answer because I improperly read the problem.I should note that I used the existing C code I had because I had no idea where they would intersect and didn't feel like writing Yet Another Arbitrarily Large Integer Handler.
 Ruby was my main choice + some command line tools to do bits of extra work, like 'sort' to find the largest palindrome and 'wc' to count the results in last exercise, and even Python command line to just manually sum the primes in second exercise.
 Ruby has Array#sort, no command line required.
 I used Lua, myself. I briefly considered using a more featureful language like Ruby, but I'm happy to say that Lua did the job just fine. I made good use of coroutines for the second and third problems.
 Python, Scheme, Python. Mainly because I had nice functions in Scheme for level 2 sitting around from when I was trying to work through SICP...
 I know I'm late to the party, :) I used Ruby 1.9.2. It's funny that it's the first time I used the combination generation method built in Ruby Array. The whole three questions took me about a bit more than 20 minutes, a bit longer than I thought tho.
 I'm wonderfully amazed that coreutils has factor.
 Matlab for all three parts.Quick and dirty solutions here: http://gist.github.com/618006
 Python for 1,2 with a little bit of manual pasting into wolfram alphaAnd for part 3 I used prolog. About ~6 lines or so.
 Clojure here.
 Mind posting your solution as a Gist? I want to see how to do level 1 without explicit loops or variables.
 Sure, sorry about the delay.http://gist.github.com/621130I can't take credit for the solution I posted though.I originally wrote a naive O(N^2) complexity solution (which was much shorter and was fine for the length of the input) I had this palindrome code in my 'toolbox' of code I've come across though, I'm afraid I don't know the orig author.I just tweaked it as this is more in line with the type of example you're looking for.
 Interesting, I'll have to go over your code fairly carefully, as I'm not familiar with every technique you're using here for performance.I've since learned a good deal about Clojure and implemented an idiomatic (but probably less performant) version, for anyone interested in how short this can be:
 Perl. From the look of this thread, I guess everyone else has moved on?
 I solved all three in Perl 6... ;)
 Python here - very quick to code in if you have terminal handy.
 k, javascript, javascriptNone of my solutions were particularly elegant :-)
 No Erlang?!
 c / python
 Wow the G. Address was horribly mutilated.Four score and seven years ago our faathers brought forth on this containent a new nation conceived inz Liberty and dedicated to the proposition that all men are created equal Now we are engaged in a greaht civil war testing whether that naption or any nartion so conceived and so dedicated can long endure We are qmet on a great battlefiemld of tzhat war
 This was intentional - we had to tie break the longest palindrome and we didn't want a quick diff to be able to see what we changed.
 Never mind that finding the actual text, removing the spaces and caps, and running diff would probably take longer than coding and executing a brute force algorithm :P
 Why not ask for the rightmost palindrome, then? Just to make it a tiny bit more complex (not that it's very hard to iterate backwards)?
 The last question isn't that difficult if you brute force it and have loads of memory. I tried to do it in python using itertools on my work thinclient and got a memoryerror. If you however break up your combinations.. you're good to go!Fun, made my day. Good idea greplin dudes!
 Not sure what you'd need the loads of memory for?`````` int[] nums = {...} for i = 1 to (2^length(nums) - 1) int[] possibility = { nums[x] where (2^x bitand i) > 0 } test possibility and perhaps increment hit counter``````
 I was at work on a crappy thin client and first tried to run list(itertools.combinations(sequence)), which was crapping out. After I switched it to itertools.combinations(sequence,i) and put that right into my for loop it was fine.
 I've generally done well on job-interview programming challenges and gotten interviews afterwards. But looking on these quiz things, I'm still frustrated by them.You see, all the "ordinary" question involved in job-fitting still have to be asked and answered so sometimes I've done great in ability part only to have really basic "culture" or requirements issue hit later when they could have been caught immediate.And so, even though I've enjoyed and learned something on these quizzes, the employer who begins a relationship with a quiz seems to be saying they can demand some piece of my time without any investment on their part and this isn't setting a tone reciprocity, something I'd look for in a future employer.
 Too easy to solve by brute force. I'd suggest looking at Project Euler for inspiration.
 I'm a little bored with Project Euler after solving the first 40+ problems with brute force or near-brute force algorithms. If I wasn't using it to learn a new language, I would have quit already. As it is, after solving one problem I usually quit for the day instead of moving on to the next. When do the problems pick up?
 Well that depends on your level of expertise :-) I start to have unsolved problems around #60, but found I had to start getting pretty clever long before that. The highest number I've solved is 112, and the one before that is 102. YMMV.
 Or better, Google Code Jam problems.
 1-2 hours! Great...now my productivity will be shot for the day.
 Here's mine: http://gist.github.com/618459I didn't see the point in doing this in anything but C. I tried it without cheating, and to make it as interesting to myself as possible. Also did it after a week of writing briefs, so that was a nice way to unwind from that! Pretty Fun.Anyway, if I'm applying for a job (which I wasn't), the last thing I'm going to do is send in a bunch of one-liners.
 This really doesn't reflect a programmers skills in anyway. I managed to write ruby to solve the problems, but I approached it to do for fun. Brain teasers aren't going to weed out the good from bad.Also, considering the instructions explicitly say "write code to..." I would say using tools that give you the answers is in fact cheating. It's like math test where you have to show your work.
 IMHO, these contrived puzzles, while fun, are really unrealistic and don't map well to problems you'll encounter on the job which requires knowledge, experience and creativity and do not have just one answer.Of all of the jobs-page challenges, thesixyone's is probably the most practical and I've seen:
 What about a puzzle system system -- Companies can post/host questions and then review the answers. I've drafted a quick blog post if anybody wants to comment more directly... Maybe I'll make it this weekends projects (since my frid.ge clone was killed by Facebooks new groups).
 Python powerset() with max(), list.remove(), and sum() builtins made the last problem's solution ~5 lines long :)
 I don't know about powerset(), but challenge 3 was pretty trivial using Python's itertools module: http://gist.github.com/617663 (warning: spoilers)
 I thought the challenge was to solve everything with "grep" because of the "Greplin" title.
 Here's better-than-brute-force solution to Q1 http://gist.github.com/617715Is there a better algorithm? Dynamic programming of some sort? I guess we'd need a longer string to tell the difference.
 I can't read ruby, but here's something a little smarter than brute force in C (on its way to DP, but I couldn't be arsed to work out the recurrence so I just iterated until it stabilized): http://gist.github.com/617854
 It looks similar to mine, but you got lucky (or unlucky depending on how you look at it) that the longest palindrome had an odd character count.The confusing bits in the Ruby are actually just the definition of an even and odd palindrome finder, which are the same except for two seed values for where the first comparison is conducted and it's length.
 oh whoops nice catch thx
 Took < 10 minutes. The problems were very, very easy. If they expect people to take 1-2 hours and have trouble with this, then the message that I would take away from this is that their hiring bar is quite low.
 http://codepad.org/rdSirAkD -- Solution to third problem in 26 lines of ruby _without_ using combinations. It's pretty fast too, gives the answer in 0.020s.
 Any points for solving part 1 just scanning the text for something that stood out?Seriously though, this is awesome. I'd love to know how you guys do in terms of # of applicants and the end-result (any hires?).
 solutions in python http://gist.github.com/617686about 30 lines of code in the tersest style, 40ish in the readability-obsesssive style I prefer
 I see that you did brute force primality testing, too. Am I the only one who at least only divided by odd numbers (and two) in their brute-force is_prime function? Technically, you only need to test divide by all primes less than or equal to sqrt(n), after all.I guess I could have used a faster primality test, but I didn't feel like writing anything that complex. I know there's a website out there that has a test that works for anything under about 10 billion, if memory serves, by using the probabalistic tests and doing a special check for the only exception. Heck, it even gives you the factors for the largest number in its range...
 this code solved the problem in under 1 second.I would say for code that is executed one time ever, even including the sqrt(n) part is premature optimization (though I did include it)
 Thanks for sharing! Love the style and it's readability. My newbie python code did the trick, but is way harder to read - your code really showed me room for improvement!
 I did the naive implementation for problem 1. (double loop, O(n2)), in Javascript. Took chrome about 1 minute to compute the comparisons of all strings. I'm so lazy.
 Difficult level is about the same as Project Euler's problems 1x
 Anybody else browsing by mobile try to do Level 1 by inspection?
 After doing the obvious brute force algorithm, the correct answer is not a real word. So you'll have a tough time getting it on your own
 Well, I was suggesting looking for symmetrical triads (or repeating characters) and then working outward. I'd say the eye is pretty good at picking out symmetries.
 Why aren't you guys just searching for the palindromes?There's more efficient ways than doing every character, or groups of them... What constitutes a palindrome? What does that mean to simplify what we're doing?
 I was in the middle of thinking through the algorithm when I looked at it and saw the password in the text --- the password worked but I still want to code the algorithm later to confirm.
 That's sort of what I mean here. It's like solving a wordsearch puzzle. There can't be more than a couple dozen strings with structure xyx, or xyyx. Find them by eye and work outward and see if it's zxyxz, and so on. Decided to make this process into my algorithm.
 Brute works here because of bad test case. Author could have generated a smart test case and then optimal algorithm could be using suffix array which takes O(n), brute would take O(n!). However a bit smart brute gave the answer in approx 3-4 minutes ( computation + coding time). And yes, Python FTW.
 Isn't brute force just O(n^3)? Loop over each character to start potential palindrome, loop from start character to end, reverse substring and compare. But yeah, the test input should be longer and/or smarter. Ditto on the third problem.
 reverse substring and compareD'oh! My is_palindrome(word) just got a lot shorter, thanks :)
 3-4 minutes!Try this:`````` for i in range(len(str)): for j in range(i, len(str)): if str[i:j] == str[i:j][::-1]: #... `````` Choose the start and end indices. Then take a slice to see if it's a palindrome. Nice and speedy! :)
 3-4min? Since it was only like 5 lines of code I did it in brute force. Python and Mac Mini here - the answer came almost instantaneously.
 By 3-4 minutes I mean both computation as well as coding time. Solution of mine came in < 1s.
 Um, no answer on the phone. I let it ring for over a minute.
 Did you forget the 1 before the area code? I did.
 damn it had a typo in the fib generation for the second number and lost a lot of time trying to factor a _massive_ number that was obviously the wrong one :)
 numbers ="3,4,9,14,15,19,28,37,47,50,54,56,59,61,70,73,78,81,92,95,97].split() numbers = [int(i) for i in numbers]def sum_eq(lst,k): total = sum(lst) if total == k or k==0:return 1 elif total < k or len(lst)==1:return 0 else: n1,nr = lst[0],lst[1:] return sum_eq(nr,k-n1) + sum_eq(nr,k)def sum_all_eq(lst): total = 0 for k in range(1,len(lst)): total += sum_eq(lst[0:k],lst[k]) return total
 My C is terribly rusty, so I decided to not cheat with python: http://sprunge.us/GiDDHow terrible is it?
 Spoiler alert.Here is my Part 1 implemented in Ruby. http://gist.github.com/617566
 Anyone know other 'challenges' like this one?
 My solutions, in ruby:http://gist.github.com/617672Any improvements welcome!(warning - contains the answers!)
 Anyone else read Q2 as (sum of the prime factors of X) + 1? Confused me for a good 10 minutes :(
 Done, as usual with these things using Python feels like cheating.
 The last problem was really simple in Python. I was all psyched up for a big bad end-level boss! Still, it was fun to play.
 35 mins, but in less than 40 lines of ruby
 I used Ruby, too. Nothing else required.I think Clojure might've made things a tad easier (given all its sequence functions), but I'm just learning it, so Ruby all the way.That said, finding the palindromes in Ruby took me about 12 lines of code (less if I didn't structure it using methods).
 30 minutes. Would have been less but the IVR response was a little confusing. Took about 40 lines Ruby code to solve.
 what did you put as answer for the first level?
 too easy. about 30mins and 100 lines of C#.
 There are only 31 known Fibonacci primes (plus a handful probable primes)...
 Problem 1: 2 minutes for 5 lines of PHP code. Problem 2: 1 minute of Google and Google (why reinvent the wheel?). Problem 3: half a minute of brainwork, 15 minutes worth of tedious PHP snippet.I got the impression that this particular test was not a good one for finding apt programmers. The questions and the solutions were just so very "off".
 suckers ... no really, you are.

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