Or even better, what if a site could combine all my social feeds, and make sure that I only see the most recent update from a person across all their networks.
I haven't used it but it looks like the author would like http://www.friendfeed.com. Maybe not the best implementation, but a start.
Of course, most people don't realise this until they're already suffering from the problem. When I had a Facebook account, I regularly "pruned" people from my friends list. Now I have a twitter account I try to minimise the number of people I follow, and the number of uninteresting posts I make.
Even interesting people have spammy days where they most too much (like at a conference) or stuff that's uninteresting to you. Permanently unfollowing is not a good solution to that.
I've been thinking about adding something like this to http://friendbinder.com for a while now, though it's quite hard to get the filtering right to pick out the best stuff (I don't think just filtering the latest update is good enough).
but as for twitter, I agree completely with the author's assessment
I'm signing up to friendbinder now, though, and I'd be happy to brainstorm with you.
A better solution would systematically rank incoming message types based on prior determinations of importance of related messages (bayesian) and weight can be added to a particular user's messages (positive and negative) to help the cream rise to the top. The addition of collaborative filtering would help those that aren't interested in flagging their own incoming messages (up/down vote) still reap the benefits of the crowd.
Maybe a "pin" and "unpin" feature that would pin these people to the top could work.
But, yes, I didn't explore the details too much about the "show more" feature. Would you list a count of the "unread items" from friends? Or would you need a slider that says "Show updates from the last 48 hours?" Then, would you need to couple this with some algorithm that bubbled up to the top the friends that you clicked "show more" on frequently? I'm not sure about the answers to all these questions, so I'll leave up to developers to figure it out.