Agreed, but the tutorial is actually quite good and the syntax (mostly) makes sense to me now.
What I don't understand is that writing a stream that unlatches a "variable" (a thing bound to a latch) executes once per time the variable is set, but it's not clear why the same code bound to a constant doesn't loop infinitely.
What I don't understand is that writing a stream that unlatches a "variable" (a thing bound to a latch) executes once per time the variable is set, but it's not clear why the same code bound to a constant doesn't loop infinitely.
i.e.
i = [int\] <- 10; \i -> std.out;
executes once because i was set once.
i = [int\] <- 10; i -> std.out;
executes once because...